LEAP YEAR

Write a program to check whether a given year is a leap year or not. 

Input Format: 

Input consists of a single integer.

Output Format: 

Output consists of a single line. Refer sample output for details. 

Sample Input 1: 

1988 

Sample Output 1: 

1988 is a leap year 

Sample Input 2: 

1994 

Sample Output 2: 

1994 is not a leap year 

Hint: 

In general terms the algorithm for calculating a leap year is as follows... 

A year will be a leap year if it is divisible by 4 but not by 100. If a year is divisible by 4 and by 100, it is not a leap year unless it is also divisible by 400. 

Thus years such as 1996, 1992, 1988 and so on are leap years because they are divisible by 4 but not by 100. For century years, the 400 rule is important. Thus, century years 1900, 1800 and 1700 while all still divisible by 4 are also exactly divisible by 100. As they are not further divisible by 400, they are not leap years.

Code:

  #include<stdio.h>
int main(){
  int y;
  scanf("%d",&y);
  if((y%400==0))
    printf("%d is a leap year\n",y);
  else if(y%100==0)
    printf("%d is not a leap year\n",y);
  else if (y%4==0)
      printf("%d is a leap year\n",y);
    else 
      printf("%d is not a leap year\n",y);
  return 0;
}